#include <stdio.h>
#define S(z) (z*z)
void foo(int x, int *py)
{
int n = S(x+1);
x = *py;
*py = n;
}
int main()
{
int a = 2;
int b = 10;
foo(a, &b);
++b;
printf("a = %d b= %d\n", a, b);
return 0;
}
[Answer]
a = 2 b= 6
a = 2代入S(2+1)則2+1*2+1=5,不是3*3=9
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